Step-by-step explanation:
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Let the digit in units place be x.
Then, digit in ten's place =3x
So, original number =10(3x)+x=31x
On interchanging the digits, new number =10x+3x=13x
According to the given condition,
31x+13x=88
⇒44x=88
⇒x=2
So, the original number is 31x or 31×2=62.
On the other hand, if we consider the digit in ten's place as x, then the digit in the unit's place will be 3x.
So, original number =10(x)+3x=13x
On interchanging the digits, new number =10(3x)+x=31x
13x+31x=88
So, the original number is 13x or 13×2=26.
Here, both answers are correct, as 26+62=88.
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Verified answer
Step-by-step explanation:
Please mark me brainlist
Let the digit in units place be x.
Then, digit in ten's place =3x
So, original number =10(3x)+x=31x
On interchanging the digits, new number =10x+3x=13x
According to the given condition,
31x+13x=88
⇒44x=88
⇒x=2
So, the original number is 31x or 31×2=62.
On the other hand, if we consider the digit in ten's place as x, then the digit in the unit's place will be 3x.
So, original number =10(x)+3x=13x
On interchanging the digits, new number =10(3x)+x=31x
According to the given condition,
13x+31x=88
⇒44x=88
⇒x=2
So, the original number is 13x or 13×2=26.
Here, both answers are correct, as 26+62=88.
hope it was helpful to you please mark as brainliest