Answer:
(5√3+√2)/(√3+√2)
=(5√3+√2)(√3-√2)/(√3+√2)(√3-√2)
=(15+√6-5√6-2)/(3-2)
=(13-4√6)
[tex]\tt 5[/tex]
Step-by-step explanation:
We have,
[tex]\tt \dfrac{5\sqrt{3} + \sqrt{2}}{\sqrt{3}+\sqrt{2}}[/tex]
Multiply numerator and denominator by [tex] \tt \sqrt{3} - \sqrt{2} [/tex]
[tex]\tt \dfrac{5\sqrt{3} + \sqrt{2}}{\sqrt{3}+\sqrt{2}}× \dfrac{\sqrt{3}-\sqrt{2}}{\sqrt{3}-\sqrt{2}}[/tex]
[tex]\tt \dfrac{5(3-2)}{3-2} = \dfrac{5×1}{1} = 5[/tex]
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Answers & Comments
Answer:
(5√3+√2)/(√3+√2)
=(5√3+√2)(√3-√2)/(√3+√2)(√3-√2)
=(15+√6-5√6-2)/(3-2)
=(13-4√6)
Verified answer
Answer:
[tex]\tt 5[/tex]
Step-by-step explanation:
We have,
[tex]\tt \dfrac{5\sqrt{3} + \sqrt{2}}{\sqrt{3}+\sqrt{2}}[/tex]
Multiply numerator and denominator by [tex] \tt \sqrt{3} - \sqrt{2} [/tex]
[tex]\tt \dfrac{5\sqrt{3} + \sqrt{2}}{\sqrt{3}+\sqrt{2}}× \dfrac{\sqrt{3}-\sqrt{2}}{\sqrt{3}-\sqrt{2}}[/tex]
[tex]\tt \dfrac{5(3-2)}{3-2} = \dfrac{5×1}{1} = 5[/tex]