hope it helps..........
Solution:
Given (√3+√5)/(√2-1)
Rationalising the denominator,
we get
= [(√3+√5)(√2+1)]/[(√2-1)((√2+1)]
= [√6+√3+√10+√5][(√2)²-1²]
/* (a+b)(a-b) = a²+b² */
= (√3+√5+√6+√10)/(2-1)
= (√3+√5+√6+√10)
••••
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Answers & Comments
hope it helps..........
Solution:
Given (√3+√5)/(√2-1)
Rationalising the denominator,
we get
= [(√3+√5)(√2+1)]/[(√2-1)((√2+1)]
= [√6+√3+√10+√5][(√2)²-1²]
/* (a+b)(a-b) = a²+b² */
= (√3+√5+√6+√10)/(2-1)
= (√3+√5+√6+√10)
••••