Answer:

To find the stopping potential, we need to use the equation:

Stopping Potential = Energy of Incident Photon - Work Function

First, we need to convert the wavelength to energy using the equation:

Energy = (hc) / λ

where:

h = Planck's constant = 6.626 × 10^(-34) J·s

c = speed of light = 3 × 10^8 m/s

λ = wavelength = 155 nm = 155 × 10^(-9) m

Plugging in the values:

Energy = (6.626 × 10^(-34) J·s × 3 × 10^8 m/s) / (155 × 10^(-9) m)

Calculating the energy of the incident photon gives:

Energy = 4.04645 × 10^(-19) J

Next, we need to convert the energy to electron volts (eV) using the conversion factor:

1 eV = 1.6 × 10^(-19) J

Energy = (4.04645 × 10^(-19) J) / (1.6 × 10^(-19) J/eV)

Energy ≈ 2.529 eV

Finally, we can calculate the stopping potential using the equation:

Stopping Potential = Energy of Incident Photon - Work Function

Stopping Potential = 2.529 eV - 5 eV

Stopping Potential ≈ -2.471 eV

Since the stopping potential cannot be negative, we take the absolute value:

Stopping Potential ≈ 2.471 eV

The correct answer is not provided in the given options.

Explanation: