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Answer:

The total energy of an electron in a hydrogen atom can be expressed as the sum of its kinetic energy and potential energy. The given energy of the electron in the ground state is -13.6 eV.

In the first excited state, the electron gains energy, and this energy is used to overcome the attractive force between the electron and the nucleus. As the electron moves farther away from the nucleus, its potential energy increases, while its kinetic energy decreases.

The energy difference between the first excited state and the ground state is 13.6 eV (since the electron has gained energy). This energy difference is used to overcome the attractive potential energy, so the kinetic energy will be equal to this energy difference.

So, the kinetic energy in the first excited state is:

Kinetic energy = Energy difference = 13.6 eV

Therefore, the correct answer is (A) 13.6 eV.

Explanation:

Answer:

c option is correct The total energy of the electron in the hydrogen atom in the ground state is -13.6 eV. Which of the following is its kinetic energy in the first excited state?