1. Given n = 12; [tex] \sf \large{ \overline{x}} = 120[/tex]ml; s = 6. The parent population is normally distributed.
Find:
a. The point estimate.
b. The interval estimate of mean.
● n = 12.
● [tex] \sf \large{ \overline{x}} = 120[/tex]ml.
● s = 6.
n = 12, [tex] \sf \large{ \overline{x}} = 12[/tex]ml, s = 6.
a. The point estimate:
Point estimate = [tex] \sf \large{ \overline{x}}[/tex].
= 120
[tex] { \boxed{ \sf \large \color{red} \therefore Poin t \: estimate = 120.}}[/tex]
________________________________________
[tex] \sf \large = { \overline{x}} + \frac{2.5}{ \sqrt{n} } [/tex]
[tex] \sf \large = 120 + \frac{2.576 \times 6}{ \sqrt{12} } [/tex]
[tex] \sf \large = 120 + 4.46 = 124.46[/tex]
[tex]{ \boxed{ \sf \large \color{red} \therefore Interval \: estimate = 124.46.}}[/tex]
[tex]{ \boxed{ \sf \large \color{blue}a . \: Point \: estimate = 120.}} \\ \\ \\ { \boxed{ \sf \large \color{blue}b . \: Interval \: estimate = 124.46.}}[/tex]
Hope you have satisfied. ⚘
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Verified answer
Question:-
1. Given n = 12; [tex] \sf \large{ \overline{x}} = 120[/tex]ml; s = 6. The parent population is normally distributed.
Find:
a. The point estimate.
b. The interval estimate of mean.
Given:-
● n = 12.
● [tex] \sf \large{ \overline{x}} = 120[/tex]ml.
● s = 6.
To Find:-
a. The point estimate.
b. The interval estimate of mean.
Solution:-
n = 12, [tex] \sf \large{ \overline{x}} = 12[/tex]ml, s = 6.
a. The point estimate:
Point estimate = [tex] \sf \large{ \overline{x}}[/tex].
= 120
Answer:-
[tex] { \boxed{ \sf \large \color{red} \therefore Poin t \: estimate = 120.}}[/tex]
________________________________________
b. The interval estimate of mean.
[tex] \sf \large = { \overline{x}} + \frac{2.5}{ \sqrt{n} } [/tex]
[tex] \sf \large = 120 + \frac{2.576 \times 6}{ \sqrt{12} } [/tex]
[tex] \sf \large = 120 + 4.46 = 124.46[/tex]
Answer:-
[tex]{ \boxed{ \sf \large \color{red} \therefore Interval \: estimate = 124.46.}}[/tex]
________________________________________
Answers:-
[tex]{ \boxed{ \sf \large \color{blue}a . \: Point \: estimate = 120.}} \\ \\ \\ { \boxed{ \sf \large \color{blue}b . \: Interval \: estimate = 124.46.}}[/tex]
________________________________________
Hope you have satisfied. ⚘
N=12
X=6