Answer:0
Step-by-step explanation:
given :a/b+b/a=1
a^2+b^2/ab=1
a^2+b^2=ab
Now , a^3+b^3=(a+b)(a^2+b^2-ab)
= (a+b)(ab-ab)
=(a+b)(0) =0
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Verified answer
Answer:0
Step-by-step explanation:
given :a/b+b/a=1
a^2+b^2/ab=1
a^2+b^2=ab
Now , a^3+b^3=(a+b)(a^2+b^2-ab)
= (a+b)(ab-ab)
=(a+b)(0) =0