Step-by-step explanation:
Given question is from quadratic equations
please read all fomulaes related to this chapter to understand the answer more easily
Answer:
since a&b are zeros of eq. x^2+3x-2=0 so a&b became its roots.
As we know that: sum of roots (a+b)= -3/1
product of roots(ab)= -2/1
(1/a^3 +1/b^3) = (a^3+b^3)/(ab)^3
= {(a+b)^3-3ab(a+b)}/(ab)^3
= {(-3)^3 -3(-2)(-3)}/(-2)^3
=45/8
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Answers & Comments
Step-by-step explanation:
Given question is from quadratic equations
please read all fomulaes related to this chapter to understand the answer more easily
Verified answer
Answer:
since a&b are zeros of eq. x^2+3x-2=0 so a&b became its roots.
As we know that: sum of roots (a+b)= -3/1
product of roots(ab)= -2/1
(1/a^3 +1/b^3) = (a^3+b^3)/(ab)^3
= {(a+b)^3-3ab(a+b)}/(ab)^3
= {(-3)^3 -3(-2)(-3)}/(-2)^3
=45/8