Question 2 (1) If R₁ and R₂ respectively are the remainders when the polynomial p(x) = kx² + 3x² - 13 and f(x) = 2x³ - 5x-k are divided by (x-4), find the value of k if R₁+R₂= 269.
To find the value of k, we need to divide the given polynomials p(x) and f(x) by (x-4) and then equate the remainders to find a relation between k, R₁, and R₂. Since both p(x) and f(x) are being divided by (x-4), the remainders will be the values of p(4) and f(4) respectively.
Let's start by finding the remainders R₁ and R₂:
Remainder R₁ for p(x) = kx² + 3x² - 13 when divided by (x-4):
To find R₁, evaluate p(x) at x = 4:
R₁ = p(4) = k(4)² + 3(4)² - 13
R₁ = 16k + 48 - 13
R₁ = 16k + 35
Remainder R₂ for f(x) = 2x³ - 5x - k when divided by (x-4):
To find R₂, evaluate f(x) at x = 4:
R₂ = f(4) = 2(4)³ - 5(4) - k
R₂ = 2(64) - 20 - k
R₂ = 128 - 20 - k
R₂ = 108 - k
Now, according to the given information, the sum of R₁ and R₂ is equal to 269:
To find the remainders R₁ and R₂ when dividing the polynomials p(x) and f(x) by (x-4), we can use the Remainder Theorem, which states that when a polynomial f(x) is divided by (x-a), the remainder is f(a).
1. For p(x) = kx² + 3x² - 13:
When dividing p(x) by (x-4), we substitute x = 4 into the polynomial:
Answers & Comments
Step-by-step explanation:
To find the value of k, we need to divide the given polynomials p(x) and f(x) by (x-4) and then equate the remainders to find a relation between k, R₁, and R₂. Since both p(x) and f(x) are being divided by (x-4), the remainders will be the values of p(4) and f(4) respectively.
Let's start by finding the remainders R₁ and R₂:
Remainder R₁ for p(x) = kx² + 3x² - 13 when divided by (x-4):
To find R₁, evaluate p(x) at x = 4:
R₁ = p(4) = k(4)² + 3(4)² - 13
R₁ = 16k + 48 - 13
R₁ = 16k + 35
Remainder R₂ for f(x) = 2x³ - 5x - k when divided by (x-4):
To find R₂, evaluate f(x) at x = 4:
R₂ = f(4) = 2(4)³ - 5(4) - k
R₂ = 2(64) - 20 - k
R₂ = 128 - 20 - k
R₂ = 108 - k
Now, according to the given information, the sum of R₁ and R₂ is equal to 269:
R₁ + R₂ = 269
(16k + 35) + (108 - k) = 269
Now, solve for k:
16k + 35 + 108 - k = 269
15k + 143 = 269
Subtract 143 from both sides:
15k = 126
Now, divide both sides by 15 to solve for k:
k = 126 / 15
k = 8.4
So, the value of k is 8.4
Answer:
To find the remainders R₁ and R₂ when dividing the polynomials p(x) and f(x) by (x-4), we can use the Remainder Theorem, which states that when a polynomial f(x) is divided by (x-a), the remainder is f(a).
1. For p(x) = kx² + 3x² - 13:
When dividing p(x) by (x-4), we substitute x = 4 into the polynomial:
R₁ = p(4) = k(4)² + 3(4)² - 13 = 16k + 48 - 13 = 16k + 35.
2. For f(x) = 2x³ - 5x - k:
When dividing f(x) by (x-4), we substitute x = 4 into the polynomial:
R₂ = f(4) = 2(4)³ - 5(4) - k = 2(64) - 20 - k = 128 - 20 - k = 108 - k.
Now, we are given that R₁ + R₂ = 269. Let's substitute the expressions for R₁ and R₂:
(16k + 35) + (108 - k) = 269
Now, let's solve for k:
16k + 35 + 108 - k = 269
Combine like terms:
15k + 143 = 269
Subtract 143 from both sides:
15k = 126
Divide by 15:
k = 126/15
k = 8.4
Therefore, the value of k is 8.4.
Step-by-step explanation: