Answer:
Use the quadratic formula
X= -b±√b2-4ac
2a
Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.
X2-7X-8=0
a=1
b=-7
c=-8
X= -(-7)± √(-7)²-4.1(-8)
2-1
[tex]{\huge{\pmb{\underline{\underline{\boxed{\sf{\color{cyan}{♡}\:{\color{orange}{Answer}{\color{cyan}\:{♡}}}}}}}}}} [/tex]
Method followed: Quadratic factorization using splitting of middle term.
[tex] \sf{:⟹ {x}^{2} - 7x - 8 = 0 }[/tex]
[tex] \sf{:⟹ {x}^{2} - 8x + 1x - 8 = 0 }[/tex]
[tex] \sf{:⟹ x( x - 8) + 1(x - 8) = 0 }[/tex]
[tex]\sf{:⟹ (x-8)(x+1)} = 0[/tex]
[tex] {\sf{:⟹} \: \: }{\boxed{\sf{ x_{1} =8 \: ; \: x_{2} = - 1 }}}[/tex]
Hope this helps uh!! :D
Thank uh!!! <33
[tex]{\color{cyan}{\underline{\rule{100pt}{2pt}}}}{\color{orange}{\underline{\rule{100pt}{2pt}}}} [/tex]
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Answers & Comments
Answer:
Use the quadratic formula
X= -b±√b2-4ac
2a
Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.
X2-7X-8=0
a=1
b=-7
c=-8
X= -(-7)± √(-7)²-4.1(-8)
2-1
[tex]{\huge{\pmb{\underline{\underline{\boxed{\sf{\color{cyan}{♡}\:{\color{orange}{Answer}{\color{cyan}\:{♡}}}}}}}}}} [/tex]
Method followed: Quadratic factorization using splitting of middle term.
[tex] \sf{:⟹ {x}^{2} - 7x - 8 = 0 }[/tex]
[tex] \sf{:⟹ {x}^{2} - 8x + 1x - 8 = 0 }[/tex]
[tex] \sf{:⟹ x( x - 8) + 1(x - 8) = 0 }[/tex]
[tex]\sf{:⟹ (x-8)(x+1)} = 0[/tex]
[tex] {\sf{:⟹} \: \: }{\boxed{\sf{ x_{1} =8 \: ; \: x_{2} = - 1 }}}[/tex]
Hope this helps uh!! :D
Thank uh!!! <33
[tex]{\color{cyan}{\underline{\rule{100pt}{2pt}}}}{\color{orange}{\underline{\rule{100pt}{2pt}}}} [/tex]