Step-by-step explanation:
[tex]x2 + 12 - 7 = 0[/tex] subtract the number
[tex]x2 + 5 = 0[/tex]
move the constant to the right-hand side and change it's signed
[tex]x { }^{2} = - 5[/tex]
take the square root of both sides of the equation and remember to use both positive and negative roots
[tex]x = + \sqrt{5l} [/tex]
write the solutions,one with a+sign and one with a-sign
[tex]x = - \sqrt{5l \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \x = \sqrt{5l} } [/tex]
the equation has 2 solutions
answer:
[tex]x1 = - \sqrt{5x2 = \sqrt{5l} } [/tex]
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Explanation:
The square root of a negative number is not a real number
Step-by-step explanation:
[tex]x2 + 12 - 7 = 0[/tex] subtract the number
[tex]x2 + 5 = 0[/tex]
move the constant to the right-hand side and change it's signed
[tex]x { }^{2} = - 5[/tex]
take the square root of both sides of the equation and remember to use both positive and negative roots
[tex]x = + \sqrt{5l} [/tex]
write the solutions,one with a+sign and one with a-sign
[tex]x = - \sqrt{5l \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \x = \sqrt{5l} } [/tex]
the equation has 2 solutions
answer:
[tex]x1 = - \sqrt{5x2 = \sqrt{5l} } [/tex]