Answer:
Given:
x2+x−20≥0
This factors as:
(x+5)(x−4)≥0
This will hold if any of the following:
• (x+5>0 and x−4>0) ⇔ x>4
• (x+5<0 and x−4<0) ⇔ x<−5
• x+5=0 ⇔ x=−5
• x−4=0 ⇔ x=4
Hence we find the solution set is:
x∈(−∞,−5]∪[4,∞)
That is:
x≤−5 or x≥4
It seems that the answer key was for a different problem, namely:
x2+x−20≤0
x<-4 or x>5
Step-by-step explanation:
(x-5)(x+4)=0
x-5 = x-5 = 0 = 5
x+4 = x-4=0 = - 4
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Answers & Comments
Answer:
Given:
x2+x−20≥0
This factors as:
(x+5)(x−4)≥0
This will hold if any of the following:
• (x+5>0 and x−4>0) ⇔ x>4
• (x+5<0 and x−4<0) ⇔ x<−5
• x+5=0 ⇔ x=−5
• x−4=0 ⇔ x=4
Hence we find the solution set is:
x∈(−∞,−5]∪[4,∞)
That is:
x≤−5 or x≥4
It seems that the answer key was for a different problem, namely:
x2+x−20≤0
Answer:
x<-4 or x>5
Step-by-step explanation:
(x-5)(x+4)=0
x-5 = x-5 = 0 = 5
x+4 = x-4=0 = - 4