Answer:
[tex] \frac{36 \times 1000}{60 \times 60} = 10 \: ms \: { - }^{1} [/tex]
New velocity = 72
[tex]km \: h { - }^{1} [/tex]
[tex] \frac{72 \times 1000}{60 \times 60} \: = 20 \: ms { - }^{1} [/tex]
Increase in energy
[tex] \frac{1}{2} m {v}^{2} \: - \: \frac{1}{2} m {u}^{2} [/tex]
[tex] \frac{1}{2}m \: (v + u) \: (v - u)[/tex]
[tex] \frac{1}{2} \times 1000 \times 30 \times 10[/tex]
= 150000 J
[tex] = 1.5 \times {10}^{5} j[/tex]
1.5 x 10⁵ J
Mwah mwah bye ty for points
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Answer:
SOLUTION:
[tex] \frac{36 \times 1000}{60 \times 60} = 10 \: ms \: { - }^{1} [/tex]
New velocity = 72
[tex]km \: h { - }^{1} [/tex]
[tex] \frac{72 \times 1000}{60 \times 60} \: = 20 \: ms { - }^{1} [/tex]
Increase in energy
[tex] \frac{1}{2} m {v}^{2} \: - \: \frac{1}{2} m {u}^{2} [/tex]
[tex] \frac{1}{2}m \: (v + u) \: (v - u)[/tex]
[tex] \frac{1}{2} \times 1000 \times 30 \times 10[/tex]
= 150000 J
[tex] = 1.5 \times {10}^{5} j[/tex]
#CARRYONLEARNING
Answer:
1.5 x 10⁵ J
Mwah mwah bye ty for points