Verified answer

Explanation:

To find : volume of CO₂ occupied at STP.

given :- mass of CO₂ = 4.4 g

[tex]\bf{formula \: used:} \\ \sf \: no. \: of \: moles \: at \: STP \: = \dfrac{volume \: in \: litre}{22.4} [/tex]

[tex]\sf \: moles \: = \dfrac{given \: mass}{molecular \: mass} \\ \\\\ \sf \: molecular \: mass \: of \: CO₂ \: = 44 \\ \\ \sf \: moles \: = \frac{4.4}{44} = \frac{1}{10} \\ \\ \sf \: putting \: all \: the \: values \: in \: formula \: we \: have : \\ \\ \sf \dfrac{1}{10} = \dfrac{volume( \: in \: litre)}{22.4} \\ \\ \sf \: volume \: = \dfrac{22.4}{10} = \red{2.24 \: litre \: }[/tex]

[tex] \bf \sf \green {hence \: volume \: of \: CO₂ \: is \: 2.24 \: litre. \: }[/tex]