Q.8 A metallic rod of length L, is rotating with an angular frequency w about its one end. Find out the induced emf produced between the ends of the rod
All points on the rod are moving perpendicular to the magnetic field. Hence, all elementary small elements of the rod induce a small potential difference and the net potential difference in the rod is the integration of the potential differences along the rod.
Motional emf in a conductor moving perpendicular to the field is given by:
ε=Bvl
The potential difference across a small element of rod at a distance l from the center, dε=Bv(dl)
Answers & Comments
Answer:
All points on the rod are moving perpendicular to the magnetic field. Hence, all elementary small elements of the rod induce a small potential difference and the net potential difference in the rod is the integration of the potential differences along the rod.
Motional emf in a conductor moving perpendicular to the field is given by:
ε=Bvl
The potential difference across a small element of rod at a distance l from the center, dε=Bv(dl)
But v=ωl⟹dε=Blωdl
Hence total emf produced across the rod,
ε=∫
0
L
B(lω)dl
=
2
1
BωL
2