Q55. The present age of a Swarup is 3 years more than three times the age of his friend parneeth. Three years ,hence the swarup's age will be 8 years more than twice the age of her friend parneeth. Find the ages of Swarup and Parneeth.
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Let the age of parneeth = x years.
Given that Swarup is 3 years more than three times the age of parneeth.
So, the age of Swarup = 3x + 3.
3 years hence:
= > Age of parneeth = x + 3.
= > Age of Swarup = 3x + 3 + 3.
Now,
Given that Swarup's age will be 8 years more than twice of parneeth.
= > 3x + 3 + 3 = 2(x + 3) + 8
= > 3x + 6 = 2x + 6 + 8
= > 3x + 6 = 2x + 14
= > 3x - 2x = 14 - 6
= > x = 8.
Then,
= > 3x + 3
= > 3(8) + 3
= > 27.
Therefore:
= > The age of Parneeth = 8 years.
= > The age of Swarup = 27 years.
Hope this helps!