Q20. Ram and Shyam start their journey from home to market via two different paths as shown in figure. Ram uses a straight path while Shyam uses a semi-circular path to reach the market. Distance from home to market is 200 m.
(I) what is the distance of ram
(ii) if shyam takes 50π s to reach market, find the average speed
(I) what is the distance of ram
(ii) if shyam takes 50π s to reach market, find the average speed
Answers & Comments
Answer:
1) distance= 200m
displacement=200m because he is travelling in a straight path
2) time= 50pi sec
total distance= 200m
average speed = total distance/total time
= 200/50pi
= 4/pi
if you want to simplify pi you can but no need teacher will give you marks don't worry
Explanation:
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Verified answer
Given:
To Find:
Solution:
(i) Distance traveled by Ram:
From the given figure, it is clear that Ram uses a straight path to reach the market. The straight path is the hypotenuse of the right-angled triangle formed by the home, market, and the path. The distance traveled by Ram can be found using the Pythagorean theorem.
Let the distance traveled by Ram be x meters.
Using Pythagorean theorem: x^2 = (200)^2 + (200)^2
x^2 = 40000 + 40000
x^2 = 80000
x = √80000
x ≈ 282.84 meters
(ii) Average speed of Shyam:
Average speed is given by the total distance traveled divided by the total time taken.
Shyam travels a semicircular path to reach the market. The circumference of the semicircle is equal to the distance from home to market (200 m).
Distance traveled by Shyam = Circumference of the semicircle = π × radius of the semicircle = π × (200/2) = π × 100 = 100π m
Average speed = Distance traveled / Time taken
Average speed = (100π m) / (50π s) = 2 m/s
Therefore,
(i) The distance traveled by Ram is approximately 282.84 meters.
(ii) The average speed of Shyam is 2 m/s.
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