Answer:

[tex]55\sqrt{2} : 14[/tex] is the right answer using [tex]\pi =\frac{22}{7}[/tex]

Explanation:

Distance:-

In one complete Circular path distance covered =[tex]2*\pi *r[/tex]

In 1 second distance covered will be [tex]\frac{2*\pi *r }{40}[/tex]

In 50 seconds distance covered will be [tex]\frac{2*\pi*r }{40}*50=\frac{55}{7} r[/tex]

Distance =

Displacement:-

In 40 Seconds it will complete one circular path means no displacement

In 10 seconds it will complete a quarter of circular path.

Displacement =[tex]\sqrt{r^2+ r^2} =\sqrt{2r^2} = \sqrt{2}*r[/tex]

Distance: Displacement =[tex]\frac{\frac{55}{7} r}{\sqrt{2} r} =\frac{55\sqrt{2} }{14}[/tex]  =  [tex]55\sqrt{2} :14[/tex]