Q.12. The population of a city increases each year by 4% of what it had been at the beginning of each year. If the population in 1999 had been 6760000.
Now Answer the following.
(a) What was the population in the year 1997.?
(i) 6230016
(ii) 6250000
(iii) 7030400
(iv) 7311616
(b) What was the population in the year 1998?.
(i) 6500000
(ii)6489600
(iii) 7030400
(iv) 7311616
(c) What is the population in the year 2000?
(i) 7030400
(ii) 7311616
(iii) 64869000
(iv) 6500000
(d) What will the population in the year 2001?
(i) 6500000
(i)6489600
(iii) 7030400
(iv) 7311616
(e) What is the difference of population in the year 1997 and 2001
(i) 1061616
(ii) 6661616
(iii) 6380400
(iv) 780400
please answer fast
in answer write the correct option and if possible then explain the solution...
hmmmm.
Answers & Comments
Answer:
Population increase=4%
present population= 6760000
1. 4%of 6760000
4/100*6760000 =27040
6760000+27040=6787040
6787040+(4/100*6787040)=7058522(approx)
(population after 2 years hence)
present population= 6760000
4% of 6760000=27040
6760000-27040= 6732960
4% of 6732960=269318.4
6732960-269318.4
=6463642(approx)
population 2 years ago