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Dasham10
@Dasham10
June 2021
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Q1. Prove that the sum of any two sides of a triangle is greater than the third side.
Q2. Prove that if two sides of a triangle are unequal, the angle opposite to the longer side is smaller.
Answers & Comments
sanskar202
Question no 1...Let ABC be a triangle
We can extend BA past A into a straight line.
There exists a point D such that DA=CA.
Therefore, from Isosceles Triangle has Two Equal Angles:
∠ADC=∠ACD
Thus by Euclid's fifth common notion:
∠BCD>∠BDC
Since △DCB is a triangle having ∠BCDgreater than ∠BDC, this means that BD>BC.
But:
BD=BA+AD
and:
AD=AC
Thus:
BA+AC>BC
A similar argument shows that AC+BC>BA and BA+BC>AC
1 votes
Thanks 3
Dasham10
Thanks so much
sanskar202
welcome send me ur number ..whtsapp
Dasham10
Why ?
lalanchoudhary867602
Answer:
Step-by-step explanation:
0 votes
Thanks 1
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Answers & Comments
We can extend BA past A into a straight line.
There exists a point D such that DA=CA.
Therefore, from Isosceles Triangle has Two Equal Angles:
∠ADC=∠ACD
Thus by Euclid's fifth common notion:
∠BCD>∠BDC
Since △DCB is a triangle having ∠BCDgreater than ∠BDC, this means that BD>BC.
But:
BD=BA+AD
and:
AD=AC
Thus:
BA+AC>BC
A similar argument shows that AC+BC>BA and BA+BC>AC
Answer:
Step-by-step explanation: