[tex]\huge\tt\bold\blue{Answer}[/tex]
We know that the sum of the exterior angles of any polygon is always 360 degrees.
Two other exterior angles are 180–127 or 53º and 180–135 or 45º.
Therefore the sum of the 5 exterior angles is 150+53+45 = 248º.
The sum of the remaining exterior angles = 360–248 or 112º
Hiee (≧▽≦)
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[tex]\huge\tt\bold\blue{Answer}[/tex]
We know that the sum of the exterior angles of any polygon is always 360 degrees.
Two other exterior angles are 180–127 or 53º and 180–135 or 45º.
Therefore the sum of the 5 exterior angles is 150+53+45 = 248º.
The sum of the remaining exterior angles = 360–248 or 112º
Hiee (≧▽≦)