Answer:

9.6m is the answer.

EXPLANATION :

Draw perpendicular OA and OB on RS and SM respectively.

Let R,S and M be the position of Reshma, Salma and Mandip respectively.

AR= AS=

2

6

= 3 cm

OR= OS= OM= 5 m [radii of circle]

In △OAR

OA

2

+ AR

2

= OR

2

OA

2

+

3 2

5 2

OA=

25−9

OA= 4 m

We know that in an isosceles triangle altitude divides the base ,

So, in △RSM

∠RCS= 90

o

RC=CM

Area of

△ORS=

2

1

×

OA×

RS

2

1

× RC× OS=

2

1

× 4× 6

RC× 5= 24

RC= 4.8 m

RM= 2RC= 2× 4.8= 9.6 m

So, distance between Reshma and Mandip is

9.6 m

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