Verified answer

Answer:

Approximately 2.94 moles of H₃PO₄ are formed.

Explanation:

To find the moles of H₃PO₄ formed, let's first calculate the moles of P₄O₁₀ formed in the first reaction and then use that to calculate the moles of H₃PO₄ formed in the second reaction.

Step 1: Calculate moles of P₄O₁₀ formed in the first reaction.

Given that the yield of the first reaction is 70%, we can calculate the moles of P₄O₁₀ formed from 7 moles of P as follows:

Moles of P₄O₁₀ formed = 70% of 7 moles of P

[tex]Moles \: of \: P_4O_{10} \: formed = 0.70 \times 7 moles[/tex]

[tex]Moles \: of \: P_4O_{10} \: formed = 4.9 \: moles (approx.)[/tex]

Step 2: Calculate moles of H₃PO₄ formed in the second reaction.

In the second reaction, 1 mole of P₄O₁₀ reacts with H₂O to form 4 moles of H₃PO₄.

Given that the yield of the second reaction is 60%, we can calculate the moles of H₃PO₄ formed from the moles of P₄O₁₀ as follows:

Moles of H₃PO₄ formed = 60% of moles of P₄O₁₀ formed

Moles of H₃PO₄ formed = 0.60 × 4.9 moles

Moles of H₃PO₄ formed = 2.94 moles (approx)

So, approximately 2.94 moles of H₃PO₄ are formed.

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