PWEDE PO PA-HELP? Thanks!! :> Find the distance between the given pairs of landmarks by using the distance formula. W T. Tirona Memorial National High School and Kalayaan Hospital I Island Cove and Binakayan Public Market * N. St. Mary Magdalene School and Municipal Hall K Aguinaldo Shrine and Binakayan Public Market A Save More and Fire Station T Water Camp and Island Cove WHAT TOWN IS FORMERLY KNOWN AS CAVITE EL VIEJO?. Created by chocolapaloma08. Math

PWEDE PO PA-HELP? Thanks!! :> Find the distance between the given pairs of la...

aldrin0521

Answer:

Step-by-step explanation:

W. a = 6

b = 15

Note that a and b are the distance of x and ys respectively.

Using Pythagorean Theorem

a²+b²=c²

It can be seen that a (the distance of x) and b (distance of y) are legs of s right triangle and c (hypotenuse) is the distance, thus creating a formula:

d² = ( xsub2-xsub1 ) ² + ( ysub2-ysub1 ) ²

d² = (-4 - 2) ² + (-12 - 3)²

d² = (-6)² + (-15)²

d² = 36+225

d²=261

d=√261

Note: d ko na lalagyan ng solution ung iba, pero un parin ung ginawa ko

I.d=9

N.d=√70

K.d=2√17

A.d=√51.25

T.d=√421

Answer is KAWIT, Cavite

Pseudonyx

Answer:

KAWIT

Step-by-step explanation:

W - T. Tirona Memorial National High School and Kalayaan Hospital.

To find the distance between two points, we should use the formula $\rm distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

We are given that the point of T. Tirona Memorial National High School is (2,3), the point of Kalayaan Hospital is (-4, -12)

$\implies \rm distance = \sqrt{(-4 - 2)^2 + (-12 - 3)^2}$

$\implies \rm distance = \sqrt{(-6^2) + (-15)^2}$

$\implies \rm distance = \sqrt{36 + 225}$

$\implies \rm distance = \sqrt{261}$

Therefore √261 is W.

I. Island Cove and Binakayan Public Market

$\rm distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

We are given that the point of Island Cove is (9,16), the point of Binakayan Public Market is (9,7).

$\implies \rm distance =\sqrt{(9-9)^2 + (7 - 16)^2}$

$\implies \rm distance = \sqrt{(0)^2 + (-9)^2}$

$\implies \rm distance = \sqrt{81}$

$\implies \rm distance = 9$

Therefore 9 is I

N. St. Mary Magdalene Church and Municipal Hall.

$\rm distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

We are given that the point of St. Mary Magdalene Church is (-2,5), the point of Municipal Hall (-6, -3)

$\implies \rm distance = \sqrt{(-6 - (-2))^2 + (-3 - 5)^2}$

$\implies \rm distance = \sqrt{(-4)^2 + (-8)^2}$

$\implies \rm distance = \sqrt{16 + 64}$

$\implies \rm distance = \sqrt{80}$

Since √80 is not given in the box, we will ignore N.

K. Aguinaldo Shrine and Binakayan Public Market

$\rm distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

We are given that the point of Aguinaldo Shrine is (1,5), the point of Binakayan Public Market is (9,7)

$\implies \rm distance = \sqrt{(9 - 1)^2 + (7 - 5)^2}$

$\implies \rm distance = \sqrt{(7)^2 + (2)^2}$

$\implies \rm distance = \sqrt{68}$

$\implies \rm distance = \sqrt{4} \times \sqrt{17}$

$\implies \rm distance = 2\sqrt{17}$

Therefore 2√17 is K.

A. Save More and Fire Station

$\rm distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

We are given that the point of Save More is (-3,3), the point of Fire Station is (-9.5,0)

$\implies \rm distance = \sqrt{(-9.5 - (-3))^2 - (0 - 3)^2}$

$\implies \rm distance = \sqrt{(-6.5)^2 + (-3)^2}$

$\implies \rm distance = \sqrt{42.25 + 9}$

$\implies \rm distance = \sqrt{51.25}$

Therefore √51.25 is A.

T. Water Camp and Island Cove

$\rm distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

We are given that the point of Water Camp is (-5,1), the point of Island Cove is (9,16).

$\implies \rm distance = \sqrt{(9 - (-5))^2 + (16 - 1)^2}$

$\implies \rm distance = \sqrt{(14)^2 + (15)^2}$

$\implies \rm distance = \sqrt{196 + 225}$

$\implies \rm distance = \sqrt{421}$

Therefore √421 is T.

$\begin{array}{| c | c | c | c | c |}\cline{1-5} \rm K& \rm A & \rm W & \rm I & \rm T\\\cline{1-5} 2\sqrt{17} & \sqrt{51.25} & \sqrt{261} & 9 & \sqrt{421}\\\cline{1-5}\end{array}$