PUTTING ELECTRONS INTO ORBITALS
Consider the situation and answer the questions that follow.
Let's pretend we are moving students into campus. The house is on 1st, 2nd, 3rd, and 4th street (the levels). There are houses on these street. The houses are called s, p, d, and f houses. The s house has 1 bedroom, the p house has 3 bedrooms, the d house has 5 bedrooms, and the f house has 7 bedrooms. In each bedroom, there is a bunk bed, so two students can sleep in a bedroom.
•How many houses on 4th street?
•How many students can live on 3rd street?
•How many bedrooms on 2nd street?
•How many students can live in a p house?
•How many bedrooms on a p house?
•How many bedrooms in an f house?
•How many students can live in an f house?
•How many students can live on first street?
•How many students can live on 2nd street?
Answers & Comments
Verified answer
Answer:
Based on the given scenario, we can answer the following questions:
• How many houses on 4th street?
There is one house on 4th street.
• How many students can live on 3rd street?
Since the s house has 1 bedroom, the p house has 3 bedrooms, the d house has 5 bedrooms, and the f house has 7 bedrooms, the total number of students that can live on 3rd street is 1 + (3 * 2) + (5 * 2) + (7 * 2) = 1 + 6 + 10 + 14 = 31 students.
• How many bedrooms on 2nd street?
There are three bedrooms on 2nd street.
• How many students can live in a p house?
Since each bedroom in the p house can accommodate two students, the p house can accommodate 3 * 2 = 6 students.
• How many bedrooms on a p house?
There are three bedrooms in a p house.
• How many bedrooms in an f house?
There are seven bedrooms in an f house.
• How many students can live in an f house?
Since each bedroom in the f house can accommodate two students, the f house can accommodate 7 * 2 = 14 students.
• How many students can live on the first street?
Since the s house has 1 bedroom, and each bedroom can accommodate two students, the first street can accommodate 1 * 2 = 2 students.
• How many students can live on the 2nd street?
Since the p house has 3 bedrooms, and each bedroom can accommodate two students, the 2nd street can accommodate 3 * 2 = 6 students.