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AkarshikaPriyadarshi
@AkarshikaPriyadarshi
May 2021
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Provo that both Triangles are congruent
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AryanTennyson
As AE is perpendicular to BC
So we have,Δ ABE & Δ ACE
Therefore, in Δ ABE & Δ ACE
= > AB = AC ( same side of triangles)
=> ang.AEB = ang.AEC (each equals 90°)
=>AE = AE (common)
Hence, Δ ABE ≈ Δ ACE
1 votes
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Answers & Comments
So we have,Δ ABE & Δ ACE
Therefore, in Δ ABE & Δ ACE
= > AB = AC ( same side of triangles)
=> ang.AEB = ang.AEC (each equals 90°)
=>AE = AE (common)
Hence, Δ ABE ≈ Δ ACE