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tanya2601
@tanya2601
August 2021
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Prove the following identity:
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boney2
√sec²∆+cosec²∆=√1+tan²∆+1+cot²∆=√tan²∆+cot²∆+2=√tan²∆+cot²∆+2cot∆tan∆
=√(tan∆+cot∆)²=tan∆+cot∆
1 votes
Thanks 2
mysticd
Hi ,
LHS =
√ ( sec² A + cosec² A )
= √ ( 1 + tan² A ) + ( 1 + cot² A )
= √ ( tan² A + cot² A + 2 )
= √ ( tan² A + cot² A + 2 tan A cotA )
= √ ( tan A + Cot A )²
= tan A + Cot A
= RHS
I hope this helps you.
:)
0 votes
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Answers & Comments
=√(tan∆+cot∆)²=tan∆+cot∆
LHS =
√ ( sec² A + cosec² A )
= √ ( 1 + tan² A ) + ( 1 + cot² A )
= √ ( tan² A + cot² A + 2 )
= √ ( tan² A + cot² A + 2 tan A cotA )
= √ ( tan A + Cot A )²
= tan A + Cot A
= RHS
I hope this helps you.
:)