Answer:
let,
5 - 2√3 be a rational number.
Therefore,5 - 2√3 = p/q [ where p and q are integer , q ≠ 0 and q and p are co- prime number ]
=> - 2√3 = p/q -5
=>- 2√3 = p - 5q / q
=> √3 = p - 5q / - 2q
we know that p/q is a rational number.
Therefore,√3 is also a rational number.
This contradicts our assumption
5 - 2√3 is an irrational number
Step-by-step explanation:
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Answers & Comments
Answer:
let,
5 - 2√3 be a rational number.
Therefore,5 - 2√3 = p/q [ where p and q are integer , q ≠ 0 and q and p are co- prime number ]
=> - 2√3 = p/q -5
=>- 2√3 = p - 5q / q
=> √3 = p - 5q / - 2q
we know that p/q is a rational number.
Therefore,√3 is also a rational number.
This contradicts our assumption
5 - 2√3 is an irrational number
Step-by-step explanation:
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