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imaditya8121
@imaditya8121
June 2022
1
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prove that the area of a triangle with vertices (t,t-2),(t+2,t+2),(t+3,t) is independent of it.
Answers & Comments
Yuichiro13
Heya User,
--> Directly Applying the formula for area of
Δ
-->
--> 2 Area
[
Δ
] = | t ( t + 2 - t ) + ( t + 2 )( t - t + 2 ) + ( t + 3 )( t - 2 - t - 2 )|
=> 2 Area [
Δ
] = | 2t + 2t + 4 - 4t - 12 |
=> 2
Area [
Δ
] = | 4t - 4t - 8 | = | -8 | = 8
=>
Area [
Δ
] = 8 / 2 = 4 ;
Hence, we see that the Area of
Δ
= 4 which is a constant .. independent of the cruel 't' :p
Well, I cud've introduced the formula but the subscripts are =_= ..
If uh need it, just ask me.. ATB for ur assignment..
0 votes
Thanks 3
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Answers & Comments
--> Directly Applying the formula for area of Δ -->
--> 2 Area [ Δ ] = | t ( t + 2 - t ) + ( t + 2 )( t - t + 2 ) + ( t + 3 )( t - 2 - t - 2 )|
=> 2 Area [ Δ ] = | 2t + 2t + 4 - 4t - 12 |
=> 2 Area [ Δ ] = | 4t - 4t - 8 | = | -8 | = 8
=> Area [ Δ ] = 8 / 2 = 4 ;
Hence, we see that the Area of Δ = 4 which is a constant .. independent of the cruel 't' :p
Well, I cud've introduced the formula but the subscripts are =_= ..
If uh need it, just ask me.. ATB for ur assignment..