Solution:Since x and y are odd positive integers we havex = 2m + 1 and y = 2n + 1=> x2 + y2 = 2m + 12 + 2n + 12= 4m2 + 4m + 1 + 4n2 + 4n + 1= 4m2 + n2 + 4m + n + 2Hence x2 + y2 is an even number but not divisible by 4.
Answer:Solution:Since x and y are odd positive integers we havex = 2m + 1 and y = 2n + 1=> x2 + y2 = 2m + 12 + 2n + 12= 4m2 + 4m + 1 + 4n2 + 4n + 1= 4m2 + n2 + 4m + n + 2Hence x2 + y2 is an even number but not divisible by 4.
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Solution:Since x and y are odd positive integers we havex = 2m + 1 and y = 2n + 1=> x2 + y2 = 2m + 12 + 2n + 12= 4m2 + 4m + 1 + 4n2 + 4n + 1= 4m2 + n2 + 4m + n + 2Hence x2 + y2 is an even number but not divisible by 4.
Answer:Solution:Since x and y are odd positive integers we havex = 2m + 1 and y = 2n + 1=> x2 + y2 = 2m + 12 + 2n + 12= 4m2 + 4m + 1 + 4n2 + 4n + 1= 4m2 + n2 + 4m + n + 2Hence x2 + y2 is an even number but not divisible by 4.
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