Given AB = CD i.e. two equal chords.To Prove AB = CD
Given AB = CD i.e. two equal chords.To Prove AB = CDProof
Given AB = CD i.e. two equal chords.To Prove AB = CDProof From ΔAOB and ΔCOD,
Given AB = CD i.e. two equal chords.To Prove AB = CDProof From ΔAOB and ΔCOD,OA = OC and OB = OD (Radii of circle)
Given AB = CD i.e. two equal chords.To Prove AB = CDProof From ΔAOB and ΔCOD,OA = OC and OB = OD (Radii of circle)∠AOB = ∠DOC
Given AB = CD i.e. two equal chords.To Prove AB = CDProof From ΔAOB and ΔCOD,OA = OC and OB = OD (Radii of circle)∠AOB = ∠DOCSo, by SAS congruency,
Given AB = CD i.e. two equal chords.To Prove AB = CDProof From ΔAOB and ΔCOD,OA = OC and OB = OD (Radii of circle)∠AOB = ∠DOCSo, by SAS congruency,ΔAOB ≅ΔCOD
Given AB = CD i.e. two equal chords.To Prove AB = CDProof From ΔAOB and ΔCOD,OA = OC and OB = OD (Radii of circle)∠AOB = ∠DOCSo, by SAS congruency,ΔAOB ≅ΔCOD∴ By CPCT we get
Given AB = CD i.e. two equal chords.To Prove AB = CDProof From ΔAOB and ΔCOD,OA = OC and OB = OD (Radii of circle)∠AOB = ∠DOCSo, by SAS congruency,ΔAOB ≅ΔCOD∴ By CPCT we getAB=CD
Given AB = CD i.e. two equal chords.To Prove AB = CDProof From ΔAOB and ΔCOD,OA = OC and OB = OD (Radii of circle)∠AOB = ∠DOCSo, by SAS congruency,ΔAOB ≅ΔCOD∴ By CPCT we getAB=CDHence proved
Answers & Comments
Step-by-step explanation:
Given
Given AB = CD i.e. two equal chords.
Given AB = CD i.e. two equal chords.To Prove
Given AB = CD i.e. two equal chords.To Prove AB = CD
Given AB = CD i.e. two equal chords.To Prove AB = CDProof
Given AB = CD i.e. two equal chords.To Prove AB = CDProof From ΔAOB and ΔCOD,
Given AB = CD i.e. two equal chords.To Prove AB = CDProof From ΔAOB and ΔCOD,OA = OC and OB = OD (Radii of circle)
Given AB = CD i.e. two equal chords.To Prove AB = CDProof From ΔAOB and ΔCOD,OA = OC and OB = OD (Radii of circle)∠AOB = ∠DOC
Given AB = CD i.e. two equal chords.To Prove AB = CDProof From ΔAOB and ΔCOD,OA = OC and OB = OD (Radii of circle)∠AOB = ∠DOCSo, by SAS congruency,
Given AB = CD i.e. two equal chords.To Prove AB = CDProof From ΔAOB and ΔCOD,OA = OC and OB = OD (Radii of circle)∠AOB = ∠DOCSo, by SAS congruency,ΔAOB ≅ΔCOD
Given AB = CD i.e. two equal chords.To Prove AB = CDProof From ΔAOB and ΔCOD,OA = OC and OB = OD (Radii of circle)∠AOB = ∠DOCSo, by SAS congruency,ΔAOB ≅ΔCOD∴ By CPCT we get
Given AB = CD i.e. two equal chords.To Prove AB = CDProof From ΔAOB and ΔCOD,OA = OC and OB = OD (Radii of circle)∠AOB = ∠DOCSo, by SAS congruency,ΔAOB ≅ΔCOD∴ By CPCT we getAB=CD
Given AB = CD i.e. two equal chords.To Prove AB = CDProof From ΔAOB and ΔCOD,OA = OC and OB = OD (Radii of circle)∠AOB = ∠DOCSo, by SAS congruency,ΔAOB ≅ΔCOD∴ By CPCT we getAB=CDHence proved
Verified answer
Answer:
Here, it is given that ∠AOB = ∠COD i.e. they are equal angles.
Now, we will have to prove that the line segments AB and CD are equal i.e. AB = CD.
Proof:
In triangles AOB and COD,
∠AOB = ∠COD (as given in the question)
OA = OC and OB = OD (these are the radii of the circle)
So, by SAS congruency, ΔAOB ≅ ΔCOD.
∴ By the rule of CPCT, we have
AB = CD. (Hence proved).