Answer:
[Inrhombusallsideareequalanddiagonolsaredifferentbutintersectat90
0
]
⇒AB=BC=CD=DA
⇒AC⊥BD
InΔABC
⇒AB=BC
⇒∴∠CAB=∠ACB
⇒AO=OC
∴∠ABO=∠CBO
andsimillarlyinΔADC
⇒AD=DC
∴correspondingangleareequal
⇒∠DAC=∠DCA
and∠CDO=∠ADO
Hence,ACbisect∠Aand∠CandBDbisects∠Band∠D
HENCE,
TRI. ADB CONGRUENT TO TRI. CDB ( SSS )
BY C•P•C•T
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Answers & Comments
Answer:
[Inrhombusallsideareequalanddiagonolsaredifferentbutintersectat90
0
]
⇒AB=BC=CD=DA
⇒AC⊥BD
InΔABC
⇒AB=BC
⇒∴∠CAB=∠ACB
⇒AO=OC
∴∠ABO=∠CBO
andsimillarlyinΔADC
⇒AD=DC
⇒AO=OC
∴correspondingangleareequal
⇒∠DAC=∠DCA
and∠CDO=∠ADO
Hence,ACbisect∠Aand∠CandBDbisects∠Band∠D
GIVEN :-
TO PROVE :-
PROOF :-
IN TRIANGLE ADB AND CDB
HENCE,
TRI. ADB CONGRUENT TO TRI. CDB ( SSS )
BY C•P•C•T