So 3+2√5 = a/b where a,b are integers and are co primes and b is not equal to 0. => √5 = (a-3b)/2b. In this since,b,3,2 are integers a-3b and 2b are integers and 2b is not equat to 0. ... => √5 is rational which is a contradiction since √5 is irrational.
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Hey!!
Definations:
Irrational number is a number which is not a rational number.
Rational number: p/q ,where p and q are integers and q ≠ 0.
Proof:
³√5 can be written as ³√5/1, where p=³√5 and q=1 ,since p is not a integer.
Therefore,³√5 is not a rational number.
Hence, It's a irrational number.
I hope this will help you!!
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Answer:
Correct Answer :
So 3+2√5 = a/b where a,b are integers and are co primes and b is not equal to 0. => √5 = (a-3b)/2b. In this since,b,3,2 are integers a-3b and 2b are integers and 2b is not equat to 0. ... => √5 is rational which is a contradiction since √5 is irrational.
Step-by-step explanation:
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