Answer:
1+tan2θtanθ=1+(1−tan2θ)(2tanθtanθ)=(1−tan2θ)1−tan2θ+(2tan2θ)=1−tan2θ1+tan2θ=1−cos2θsin2θ1+cos2θsin2θ=cos2θcos2θ−sin2θcos2θcos2θ+sin2θ=cos2θ1=sec2θ
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Answer:
1+tan2θtanθ=1+(1−tan2θ)(2tanθtanθ)=(1−tan2θ)1−tan2θ+(2tan2θ)=1−tan2θ1+tan2θ=1−cos2θsin2θ1+cos2θsin2θ=cos2θcos2θ−sin2θcos2θcos2θ+sin2θ=cos2θ1=sec2θ
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