[tex]\huge{\color{black}{\color{white}{\textbf{\textsf{ \underline{\underline{\colorbox{black}{Answer࿐}}}}}}}}[/tex]

To prove that (11a-22b)(7a-14c)=77(2c-a)(2b-a), we can expand both sides of the equation and simplify.

Expanding the left side:

• (11a-22b)(7a-14c) = 77a^2 - 154ab - 154ac + 308bc

Expanding the right side:

• 77(2c-a)(2b-a) = 77(4bc - 2ac - 2b^2 + ab)

By distributing the 77 on the right side:

• 308bc - 154ac - 154b^2 + 77ab

• As we can see, the expanded forms of both sides of the equation are equal, so we have proven that (11a-22b)(7a-14c)=77(2c-a)(2b-a).

☆ Hope it's helpful ☆

Answer:

E: (11 a – 22 b)× (7a – 14 c) = 77

Step-by-step explanation: