prove that 1 gm circumscribing a circle is a rhombus
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tamanna35
||gm. circmscribing means the sides of ||gm. PQRS are tangents to the circles ; : the tangents pass through pts. of contact be A: B: C:D; respectively. PA=PD also QB=QA RC=RB SC=SD adding all these equations we get PA+QA+RC+SC=QB+BR+PD+SD ; PQ+SR =QR+PS Or 2 PQ =2QR Or PQ=QR (adjacent side of //gm are equal) ; hence ||gm. is a rhombus
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