Step-by-step explanation:
The product of two irrational numbers is not guaranteed to be irrational. In fact, it can be either rational or irrational.
For example:
[tex] (\sqrt{2} \times \sqrt{2} = 2)[/tex], where [tex](\sqrt{2}) [/tex]is irrational but the product is rational.
[tex](\sqrt{2} \times \sqrt{3})[/tex], where both [tex](\sqrt{2})[/tex] and [tex](\sqrt{3})[/tex] are irrational, and the product is also irrational.
It depends on the specific values of the irrational numbers involved in the multiplication.
Answer:
The product of two irrational numbers is not always irrational. In fact, it can be either rational or irrational.
So, the product of two irrational numbers can be rational or irrational depending on the specific numbers involved ..
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Answers & Comments
Step-by-step explanation:
The product of two irrational numbers is not guaranteed to be irrational. In fact, it can be either rational or irrational.
For example:
1. Irrational × Irrational = Rational:
[tex] (\sqrt{2} \times \sqrt{2} = 2)[/tex], where [tex](\sqrt{2}) [/tex]is irrational but the product is rational.
2. Irrational × Irrational = Irrational:
[tex](\sqrt{2} \times \sqrt{3})[/tex], where both [tex](\sqrt{2})[/tex] and [tex](\sqrt{3})[/tex] are irrational, and the product is also irrational.
It depends on the specific values of the irrational numbers involved in the multiplication.
Answer:
The product of two irrational numbers is not always irrational. In fact, it can be either rational or irrational.
For example:
So, the product of two irrational numbers can be rational or irrational depending on the specific numbers involved ..
ᶜˡᵃⁱᶠʳ