Problem
An acid was prepared by mixng 600 ml of water and 100 ml of pure sulfuric acid. Dertermine the percentage by volume composition of sulfuric acid.
(10 points)
________________________________________
Given:
Volume of solute=________ml
volume of solvent=_________ml
Volume of solution=_________ml
Required:Percent by__________
Formula:
________________________________________
Subtitution:
Final answer:
l_________l
Answers & Comments
Answer: 14.28%
Explanation:
Given: 600 mL-solvent
100 mL-solute
700-solution
Volume of solute=100 ml
Volume of solvent=600 ml
Volume of solution=700 ml
Required: Percent by volume
Formula: % by volume= volume of solute ÷ volume of solute + solvent x 100
Final Answer: 14.28%