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A rectangular garden has a length of x+2 meter and width of x+1 meter, if the area of the garden is 42 meter squared, find the PERIMETER of the garden and express the answer in a POLYNOMIAL term.
pls do answer this ASAP huhu, ty in advance;>
A rectangular garden has a length of x+2 meter and width of x+1 meter, if the area of the garden is 42 meter squared, find the PERIMETER of the garden and express the answer in a POLYNOMIAL term.
pls do answer this ASAP huhu, ty in advance;>
Answers & Comments
Answer:
To find the perimeter of the rectangular garden, you can use the formula for the perimeter of a rectangle, which is P = 2L + 2W, where L is the length, and W is the width.
In this case, the length (L) is x+2 meters, and the width (W) is x+1 meter.
So, the perimeter (P) is:
P = 2(x+2) + 2(x+1)
Now, distribute and simplify:
P = 2x + 4 + 2x + 2
Combine like terms:
P = 4x + 6
So, the polynomial expression for the perimeter of the garden is 4x + 6 meters.
P = 2(x+2) + 2(x+1)
Now, distribute and simplify:
P = 2x + 4 + 2x + 2
Combine like terms:
P = 4x + 6
The polynomial expression for the perimeter of the garden is 4x + 6 meters. In this expression, "4x" is the binomial term.