Answer :

• 210 sq.m

Formula to use :

• [tex]\large\tt\color{green}A = \frac{(b1 + b2) \times h}{2} [/tex]

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1. What is asked in the problem?

• What is the area of the garden inside the park that shaped trapeziod.

2. What are the given facts?

• 12 meters, 18 meters and 14 meters

3. What is the formula to solve the problem?

• [tex]\large\tt\color{purple}A = \frac{(b1 + b2) \times h}{2} [/tex]

4. How is the solution done?

• 12 m + 18 m × 14 m ÷ 2 = N

5. What is the complete answer?

Solution :

• [tex]\large\tt\color{green}A = \frac{(b1 + b2) \times h}{2} [/tex]

• [tex]\large\tt\color{green}A = \frac{(12 \: m + 18 \: m) \times 14 \: m}{2} [/tex]

• [tex]\large\tt\color{green}A = \frac{30 \: m {}^{2} \times 14 \: m}{2} [/tex]

• [tex]\large\tt\color{green}A = \frac{420 \: m {}^{2} }{2} [/tex]

• [tex]\large\tt\color{red}A = 210 \: m {}^{2} [/tex]

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• Therefore, the area of the garden inside the park is 210 sq.m