Verified answer

Pre - test

1. D.
2. A.
3. D.
4. B.
5. A.

Solutions:

1. The sum of the measures of a quadrilateral is 360°.

Let N represents the measure of the other two angles

360° - (100° + 130°) = N

             2

360° - 230° = N

      2

130° = N

 2

65° = N

Therefore, each angle measures 65°.

2. The sum of the measures of the interior angles of a regular polygon is 9,000°.

Let N represents the number of sides that the polygon have.

9,000° ÷ 180° = N since interior angles has a sum of 180°

50 = N

Therefore, the polygon has 50 sides.

3. The measure of the exterior angle of a regular polygon is 20°

Let N represents the number of sides that the regular polygon have.

360° ÷ 20° = N

18 = N

Therefore, the regular polygon has 18 sides.

4. The measure of the exterior angles of an octagon are m°, 2m°. 3m°, 4m°, 5m°, 6m°, 7m° and 8m°.

Let m represents itself.

m° + 2m° + 3m° + 4m° + 5m° + 6m° + 7m° + 8m° = 360° since the sum of the measures of all extetrior angles is equals to 360°

36m° = 360°

=

m = 10

Therefore, the value of m is 10.

5. Three angles of a pentagon are 105°, 135°, and 120°.

Let N represents the other 2 angles of the pentagon.

540° - (105° + 135° + 120°) = N

540° - 360° = N

180° = N

If the other two angles of the pentagon has a sum of 180°, find the measure of each using the ratio 2:3.

Let x be the angle measure.

2x + 3x = 180

5x = 180

=

x = 36°

Using x = 2 find the angle measures.

2x = 2(36) = 72°

3x = 3(36) = 108°

Therefore, the measures of the other two angles of the pentagon are 72° and 108° respectively.

What is the measure of the angles inside the regular polygon: brainly.ph/question/2741249

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