PRACTICE EXERCISE 2:
Solve the following problem
1.) Champ spent P195. 50 for a notebook and 6 pens. The notebook cost P25.75
more than the pen. How much did he pay for the 6 pens?
2.)A pair of maong pants costs P375.95 and a shirt costs P125.50 less than the maong pants How much will be spent in all if you buy 3 shirts and 2 pairs of pants?
3.)Liza paid P17.60 for 3 chocolates and 7 candles. Each chocolate cost 5 times
as much as a candy How much more did she pay for a chocolate that a
candy?
4.)A pair of earrings Lhora bought 2 of each item She paid P4,030 20 for them
How much did she pay for each handbag?
5.)A child's piggy bank contains P5 and P10 coins The number of P10 coins is 9 less than four times the number of P5 coins. If the total amount of the coins is
P630, how many P5 and P10 coins are there?
Solve the following problem
1.) Champ spent P195. 50 for a notebook and 6 pens. The notebook cost P25.75
more than the pen. How much did he pay for the 6 pens?
2.)A pair of maong pants costs P375.95 and a shirt costs P125.50 less than the maong pants How much will be spent in all if you buy 3 shirts and 2 pairs of pants?
3.)Liza paid P17.60 for 3 chocolates and 7 candles. Each chocolate cost 5 times
as much as a candy How much more did she pay for a chocolate that a
candy?
4.)A pair of earrings Lhora bought 2 of each item She paid P4,030 20 for them
How much did she pay for each handbag?
5.)A child's piggy bank contains P5 and P10 coins The number of P10 coins is 9 less than four times the number of P5 coins. If the total amount of the coins is
P630, how many P5 and P10 coins are there?
Answers & Comments
Answer:
1.) Let x be the cost of one pen.
The cost of the notebook is P25.75 more than the cost of 6 pens.
Notebook cost = 6x + P25.75
Champ spent P195.50 in total, so we can set up the equation:
6x + P25.75 = P195.50
Subtracting P25.75 from both sides:
6x = P169.75
Dividing both sides by 6:
x = P28.29
Therefore, Champ paid P28.29 for each pen.
The total cost of 6 pens would be 6 x P28.29 = P169.74
2.) The shirt costs P125.50 less than the maong pants.
Shirt cost = Maong pants cost - P125.50
Maong pants cost = P375.95
Substituting the values:
Shirt cost = P375.95 - P125.50 = P250.45
The total cost of 3 shirts and 2 pairs of pants would be:
(3 x P250.45) + (2 x P375.95) = P1,628.25
Therefore, the total spent would be P1,628.25.
3.) Let x be the cost of one candy.
Each chocolate costs 5 times as much as a candy.
Chocolate cost = 5x
Liza paid P17.60 for 3 chocolates and 7 candies.
We can set up the equation:
(3 x 5x) + (7 x x) = P17.60
Simplifying:
15x + 7x = P17.60
Combining like terms:
22x = P17.60
Dividing both sides by 22:
x = P0.80
Therefore, one candy costs P0.80 and one chocolate costs P4.00.
Liza paid P4.00 - P0.80 = P3.20 more for a chocolate than a candy.
4.) Lhora bought 2 handbags and paid P4,030.20 in total.
Let x be the cost of one handbag.
We can set up the equation:
2x = P4,030.20
Dividing both sides by 2:
x = P2,015.10
Therefore, Lhora paid P2,015.10 for each handbag.
5.) Let x be the number of P5 coins.
The number of P10 coins is 9 less than four times the number of P5 coins.
Number of P10 coins = 4x - 9
The total amount of coins is P630.
We can set up the equation:
5x + 10(4x-9) = P630
Simplifying:
5x + 40x - 90 = P630
Combining like terms:
45x = P720
Dividing both sides by 45:
x = 16
Therefore, there are 16 P5 coins and:
Number of P10 coins = 4(16) - 9 = 55
Checking:
16 x P5 = P80
55 x P10 = P550
Therefore, the total amount of coins is P630.