Answer:

−r)qr1×(xr−p)rp1×(xp−q)pq1

=xqrq−r×xrpr−p×xpqp−q

On adding all the powers of x, we get

⇒x(qrq−r+rpr−p+pqp−q)

=xpqrp(q−r)+q(r−p)+r(p−q)

=xpqr0=1

Step-by-step explanation:

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