Answer:
Figure we obtained is Rhombus and Area is 16 unit².
Step-by-step explanation:
Given:
Coordinates of the points,
A( -4 , 4 ) , B( - 6 , 0 ) , C( -4 , -4 ) and D( -2 , 0 )
We need to plot the points in the coordinate plane and name the figure. Find the Area of the Figure.
Graph is attached after plotting.
ABCD is a Rhombus as opposite sides are parallel and all sides are equal and Diagonals are perpendicular bisector of each other.
Area of the Rhombus ABCD = Area of the ΔABD + Area of the ΔACD
From the figure,
In ΔABD
Base = 4 unit
Height = 4 unit
In ΔACD
Area of the Rhombus ABCD = 1/2 × Base × Height + 1/2 × Base × Height
= 1/2 × 4 × 4 + 1/2 × 4 × 4
= 8 + 8
= 16 unit²
Therefore, Figure we obtained is Rhombus and Area is 16 unit².
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Answers & Comments
Answer:
Figure we obtained is Rhombus and Area is 16 unit².
Step-by-step explanation:
Given:
Coordinates of the points,
A( -4 , 4 ) , B( - 6 , 0 ) , C( -4 , -4 ) and D( -2 , 0 )
We need to plot the points in the coordinate plane and name the figure. Find the Area of the Figure.
Graph is attached after plotting.
ABCD is a Rhombus as opposite sides are parallel and all sides are equal and Diagonals are perpendicular bisector of each other.
Area of the Rhombus ABCD = Area of the ΔABD + Area of the ΔACD
From the figure,
In ΔABD
Base = 4 unit
Height = 4 unit
In ΔACD
Base = 4 unit
Height = 4 unit
Area of the Rhombus ABCD = 1/2 × Base × Height + 1/2 × Base × Height
= 1/2 × 4 × 4 + 1/2 × 4 × 4
= 8 + 8
= 16 unit²
Therefore, Figure we obtained is Rhombus and Area is 16 unit².