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riyanayak143
@riyanayak143
August 2021
2
43
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plzz as fast as u can..... the fast answer will be brainliest!!!
Answers & Comments
Rahul9006276
Dekho agar samjha ma nahi aaya to puche lo
1 votes
Thanks 1
riyanayak143
or ky personal bat h
Rahul9006276
dogi tub na please do na humko pata tumare pass phone hai please do na
riyanayak143
no ye mera personal phone ni h
riyanayak143
or hm kisi ldke ko aise hi apna no. ni dete
riyanayak143
okk byy
Rahul9006276
dekar to dekho agar aacha lage to hata dena ok
Rahul9006276
please yaar
demonsking52801
bhaiya ji
demonsking52801
number sharing here is not a good idea
Rahul9006276
why bro
demonsking52801
Proof: sin 3A
= sin (2A + A)
= sin 2A cos A + cos 2A sin A
= 2 sin A cos A ∙ cos A + (1 - 2 sin^2 A) sin A
= 2 sin A (1 - sin^2 A) + sin A - 2 sin^3 A
= 2 sin A - 2 sin^3 A + sin A - 2 sin^3 A
= 3 sin A - 4 sin^3 A
Therefore, sin 3A = 3 sin A - 4 sin^3 A
0 votes
Thanks 1
Rahul9006276
ha samjha gay
demonsking52801
thanks for explanation
Rahul9006276
OK
Rahul9006276
aur kuch boliye
demonsking52801
sleep bye gn subah school hai
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Answers & Comments
= sin (2A + A)
= sin 2A cos A + cos 2A sin A
= 2 sin A cos A ∙ cos A + (1 - 2 sin^2 A) sin A
= 2 sin A (1 - sin^2 A) + sin A - 2 sin^3 A
= 2 sin A - 2 sin^3 A + sin A - 2 sin^3 A
= 3 sin A - 4 sin^3 A
Therefore, sin 3A = 3 sin A - 4 sin^3 A