Answer:
1369 it's answer ok bro
good luck
and i see u already know answer
but also cause I am good this reason I solve return for you
Step-by-step explanation:
(x1,y1) = (12,0)
(x2,y2) = (0,35)
Using distance formula,
distance=
[tex] \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } [/tex]
Putting values,
[tex] = \sqrt{ {( 0 - 12)}^{2} + {(35 - 0)}^{2} } [/tex]
[tex] = \sqrt{ {( - 12)}^{2} + {35}^{2} } [/tex]
[tex] = \sqrt{144 + 1225} [/tex]
[tex] = \sqrt{1369} [/tex]
= 37 units
So, the answer is 37 units....
Ps. best of luck for your exam....
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Answers & Comments
Answer:
1369 it's answer ok bro
good luck
and i see u already know answer
but also cause I am good this reason I solve return for you
Verified answer
Step-by-step explanation:
(x1,y1) = (12,0)
(x2,y2) = (0,35)
Using distance formula,
distance=
[tex] \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } [/tex]
Putting values,
[tex] = \sqrt{ {( 0 - 12)}^{2} + {(35 - 0)}^{2} } [/tex]
[tex] = \sqrt{ {( - 12)}^{2} + {35}^{2} } [/tex]
[tex] = \sqrt{144 + 1225} [/tex]
[tex] = \sqrt{1369} [/tex]
= 37 units
So, the answer is 37 units....
Ps. best of luck for your exam....