Answer
The equation for this reaction is
2NH3 + H2SO4 --- (NH4)2S04
The molar mass of ammonium sulphate is
[(14+4)×2]+32+(16×4)
=36+32+64
=132g
Thus 33g of ammonium sulphate =33/132 mol =0.25mol
2 mol of ammonia gas required to produce 1 mol of ammonium sulphate
Thus 0.25×2=0.50 mol of NH3 is required to produce 1 mol of ammonium sulphate.
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Answers & Comments
Answer
The equation for this reaction is
2NH3 + H2SO4 --- (NH4)2S04
The molar mass of ammonium sulphate is
[(14+4)×2]+32+(16×4)
=36+32+64
=132g
Thus 33g of ammonium sulphate =33/132 mol =0.25mol
2 mol of ammonia gas required to produce 1 mol of ammonium sulphate
Thus 0.25×2=0.50 mol of NH3 is required to produce 1 mol of ammonium sulphate.