Answer:
Q13. We know in rhombus diagonals bisect each other at right angle.
In ΔAOB
AO = 12/2 = 6cm, BO = 16/2 = 8cm
Using Pythagoras theorem in ΔAOB
AB2 = AO2 + BO2
AB2 = 62+ 82
AB2 = 36 + 64
AB2 = 100
AB =√100 = 10cm
∴Each side of a rhombus is 10cm.
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Answer:
Q13. We know in rhombus diagonals bisect each other at right angle.
In ΔAOB
AO = 12/2 = 6cm, BO = 16/2 = 8cm
Using Pythagoras theorem in ΔAOB
AB2 = AO2 + BO2
AB2 = 62+ 82
AB2 = 36 + 64
AB2 = 100
AB =√100 = 10cm
∴Each side of a rhombus is 10cm.