plz solve the whole worksheet except ques 1 and 2 solve the remaining solve all...

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rajusetu @rajusetu

May 2021 1 22 Report

plz solve the whole worksheet except ques 1 and 2
solve the remaining
solve all
donot miss anything

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Revolution

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3.) h=2 L
   r=r/2
then total surface area= $\pi r^{2} + \pi rl$
= $
now--give--the--values \\ 
 \pi * (\frac{r}{2} ) ^{2} + \pi * \frac{r}{2} *2l \\ \\ 
 \ \frac{ \pi r^{2} }{4}+ \pi rl \\ \\ 
$ $\pi r(l+ \frac{r}{4} )$

4).the volume of cone and cylinder will be same
   volume of the cylinder=πr²h
cylinder's r is= cone's r
let the height is h2
volume of the cone= $\frac{1}{3} \pi r^{2} h _{2}$
$\frac{1}{3} \pi r^{2} h _{2}$ =πr²h
cancel pi and r
h= $\frac{1}{3} h _{2}$
ratio between h2 and h is 3:1

10. volume of a cone(v)= $\frac{1}{3} \pi r^{2} h
$
= $\frac{ \pi r^{2} h}{3}$
now r=2r
h=2h
volume= $\frac{1}{3} \pi (2r) ^{2} *2h$
   = $\frac{1}{3} \pi 4 r^{2} *2h \\ \\ 
=\frac{8 r^{2} h \pi }{3}$
compare two equations....
so u will get volume=8v

12.) r=r
volume of cone= $\frac{1}{3} \pi r ^{2} h$
volume of cyliner= \pi r ^{2} H
v=v
$\pi r^{2} H=\frac{ \pi r^{2} h }{3} \\ 
H= \frac{h}{3}$
height of the cone: height of the cylinder=1:3

rajusetu when you

rajusetu answer today

rajusetu you should answer more 7 questions

rajusetu keep in mind

Revolution i can't see edit button here..then wt can i do??

Revolution 8th qn is not clear..

Revolution 7th qn is not clear...

Revolution i can't see the edge of the qn paper..it is not clear..wt can i do?

rajusetu ques 5 to 9 and ques 11

rajusetu are not answered

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