a.□ABCD is a parallelogram prove it :. /_A=/_D due to interior angle theorem
b.In parallelogram opposite sides are parallel
Answer:
Step-by-step explanation:
given: parallelogram abcd,ab=cd,ad=bc
const: join bd
to prove: 1.angle A= angle B
2.AB//CD
proof: 1.
in triangle ABD and triangle BCD
ab=cd[given]
ad=bc[given]
bd=bd[common]
therefore triangle ABD IS CONGRUENT TO TRIANGLE BCD
now,
angle A =angle B [by cpct]
2.
angle DBC= angle ADB [by cpct]
also they form alternate interior angles therefore AB//CD
HENCE PROVED
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Answers & Comments
a.□ABCD is a parallelogram prove it :. /_A=/_D due to interior angle theorem
b.In parallelogram opposite sides are parallel
Answer:
Step-by-step explanation:
given: parallelogram abcd,ab=cd,ad=bc
const: join bd
to prove: 1.angle A= angle B
2.AB//CD
proof: 1.
in triangle ABD and triangle BCD
ab=cd[given]
ad=bc[given]
bd=bd[common]
therefore triangle ABD IS CONGRUENT TO TRIANGLE BCD
now,
angle A =angle B [by cpct]
2.
angle DBC= angle ADB [by cpct]
also they form alternate interior angles therefore AB//CD
HENCE PROVED